Hello from MrBillDoesMath!
Answer:
The quadratic has NO real roots. Both roots are imaginary.
Discussion:
I believe the equation involved is 7x^2 + 1 = 5x.
7x^2 + 1 = 5x => subtract 5x from both sides
7x^2 -5x + 1 = 0
Discriminant of ax^2 + bx + c = 0 is b^2 - 4ac. In our case it is
(-5)^2 - 4 (7) (1) =
25 - 28 =
-3.
Since it is negative the quadratic has NO real roots. Both roots are imaginary.
The solutions are x = 1/14 (5 +\- i sqrt(3))
Thank you,
MrB
