From the reaction;
2Na (s) + 2 H2O(l) = H2(g) + 2 NaOH (aq)
The atomic mass of sodium is 22.99 g/mol
The number of moles of sodium will be
= 4.40/22.99
= 0.1914 moles
The mole ratio of sodium and hydrogen is 2: 1
; therefore, the number of moles of hydrogen = 0.1914/ 2
= 0.0957 moles
1 mole of hydrogen at s.t.p occupies 22.4 liters, hence 0.0957 moles will occupy; 0.0957 × 22.4 = 2.144 L
Therefore, 2.144 liters of hydrogen gas will be produced
