Greek architects considered a rectangle whose length was approximately 1.6 times its width to be the most visually appealing. find the length and width of a rectangle constructed in this manner if the sum of the length and width is 130ft
Let x-------------> the length of a rectangle y-------------> the width of a rectangle we know that x+y=130-----------> equation 1 and x=1.6y--------------> equation 2
I substitute 2 in 1 (1.6y)+y=130-------------> 2.6y=130------------> y=130/2.6------> y=50 ft x=1.6y--------> x=1.6*50---------> x=80 ft
the answer is the length is 80 ft the width is 50ft
