Respuesta :

Ryan2
Line pass to points:  (-5;0) and (0;-5)

So:

[tex] \left|\begin{array}{ccc}x&y&1\\-5&0&1\\0&-5&1\end{array}\right|=0\\ \\ 25+5y+5x=0\\ \\ 5+y+x=0\\ y=-x-5\\ \\ slope=-1 \ \ \(coeficient \ of \ "x")[/tex]
AL2006
For each unit of progress toward the right ... as 'x' increases ...
the line drops one unit.

Its slope is -1.