To solve this question, you need to put the 2/3x into the f(x). Remember that x^-1 equal to 1/x Assuming 2/3x is 2/3 *x , the calculation would be: f(x)=x^-1 f(2/3x)=(2/3*x)^-1. f(2/3x)=1/ (2x/3) f(2/3x)=3/(2x)
Assuming 2/3x is 2/(3x) , the calculation would be: f(x)=x^-1 f(2/3x)=(2/3x)^-1. f(2/3x)=1/ (2/3x) f(2/3x)=3x/2
