write an equation in slope intercept form of the line that passes through the given point and is paraell to the graph of the equation.
1) (4,2) x=-3
2) (2,-1) y=-3/2+6
3) (2,-2) y=-x-2
1.) x = -3...this is a vertical line with an undefined slope. A parallel line to a vertical line is also a vertical line. A vertical line is represented by x = a number....that number being the x coordinate of ur point(4,2). so ur parallel line is : x = 4 <== ================= 2.) y = -3/2x + 6....slope here is -3/2. A parallel line will have the same slope.
y = mx + b slope(m) = -3/2 (2,-1)...x = 2 and y = -1 now we sub into the formula and find b, the y int -1 = -3/2(2) + b -1 = -3 + b -1 + 3 = b 2 = b so ur parallel line is : y = -3/2x + 2 <== =================== y = -x - 2....the slope here is -1. A parallel line will have the same slope
y = mx + b slope(m) = -1 (2,-2)...x = 2 and y = -2 now we sub into the formula and find b, the y int -2 = -1(2) + b -2 = -2 + b -2 + 2 = b 0 = b so ur parallel equation is : y = -x + 0 which can be written as : y = -x <=
