ANSWER
[tex]P(Q \: and \: R)=0.0608[/tex]
It was given that,
[tex]P(Q) = 0.32[/tex]
and
[tex]P(R) = 0.19[/tex]
Events Q and R and independent events if and only if
[tex]P(Q \: and \: R)=P(Q) \times P(R)[/tex]
We therefore substitute the respective probabilities to obtain,
[tex]P(Q \: and \: R) = 0.32\times0.19[/tex]
[tex]P(Q \: and \: R)=0.0608[/tex]
