theants
theants theants
  • 15-10-2017
  • Mathematics
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what is the 3sqaure root of 0.027y^9 = ?

Respuesta :

jdoe0001 jdoe0001
  • 15-10-2017
[tex]\bf \sqrt[3]{0.027y^9}\qquad \begin{cases} 0.027=\frac{0027}{1000}\\ 27=3^3\\ 1000=10^3\\ y^9=(y^3)^3 \end{cases}\qquad \sqrt[3]{\cfrac{27}{1000}y^9}\implies \sqrt[3]{\cfrac{3^3}{10^3}(y^3)^3} \\\\\\ \sqrt[3]{\cfrac{3^3(y^3)^3}{10^3}}\implies \cfrac{\sqrt[3]{3^3(y^3)^3}}{\sqrt[3]{10^3}}\implies \cfrac{3y^3}{10}\implies 0.3y^3[/tex]
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