Maniac16
Maniac16 Maniac16
  • 12-10-2017
  • Mathematics
contestada

solve for x: 32^x=4^(2x+1)

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Аноним Аноним
  • 12-10-2017
Hello There!

5x = 2(2x + 1)
5x = 4x +2
x = 2

Hope This Helps You!
Good Luck :) 

- Hannah ❤
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Аноним Аноним
  • 12-10-2017
[tex]x/32^x=4^(2x+1) We move all terms to the left: x/32^x-(4^(2x+1))=0 Domain of the equation: 32^x!=0 x!=0/1 x!=0 x∈R We multiply all the terms by the denominator x-((4^(2x+1)))*32^x=0[/tex]
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