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I need help
1a. A trapezium has 2 parallel sides of length 5cm and 9cm. If the area is 21cm³. Find the distance between the parallel sides
B. In the diagram |PQ|=4cm and |TS|=6cm. If the area of the parallelogram PQTU is 32cm³. Find the area of the trapezium

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I need help1a A trapezium has 2 parallel sides of length 5cm and 9cm If the area is 21cm Find the distance between the parallel sides B In the diagram PQ4cm and class=

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MathPhys

Answer:

a. 3 cm

b. 72 cm²

Step-by-step explanation:

1a. The area of a trapezium is the average of the parallel sides times the height.

A = ½ (b₁ + b₂) h

21 = ½ (5 + 9) h

h = 3 cm

1b. PQTU is a parallelogram, so UT = 4 cm. Also, PQRS is a parallelogram, so RS = 4 cm. Therefore, RU = 4 + 4 + 6 = 14 cm.

Next, the area of a parallelogram is the base times the perpendicular height.

A = bh

32 = 4h

h = 8 cm

Therefore, the area of the trapezium is:

A = ½ (b₁ + b₂) h

A = ½ (4 + 14) (8)

A = 72 cm²

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