srutkowske366 srutkowske366

12-07-2017
Mathematics

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Let the random variable x be equally likely to assume any of the values 1/11, 2/11, or 3/11. determine the mean and variance of x.

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Аноним Аноним

12-07-2017

mean of x = (1/11 + 2/11 +3/11) / 3 = 6/11 / 3 = 2/11

variance

1/11 - 2/11 = -1/11; 2/11 - 2/11 = 0 ; 3/11 - 2/11 = 1/11

(-1/11)^2 = 1/121 , 0^2 = 0 , (1/11)^2 = 1/121

1/121 + 0 + 1/121 = 2/121

Variance = 1/121 / 3 = 1 /363

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