stressedmolly3295 stressedmolly3295

01-07-2017
Physics

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At a pressure 49 kPa, the gas in a cylinder has a volume of 11 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 4 liters, what is the new pressure?

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01-07-2017

V = (1 / p) × p0 × V0
1 / p = V / (p0 × V0)
p = (p0 × V0) / V = (49kPa × 11L) / 4L = 134.75kPa

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