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15-06-2017
Mathematics

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2 times the square root of 27 minus the square root of 48

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15-06-2017

[tex]2 \sqrt{27}- \sqrt{48}=2 \sqrt{9*3}- \sqrt{16*3} =2*3 \sqrt{3}- 4 \sqrt{3}=6 \sqrt{3}-4 \sqrt{3} = \\ =2 \sqrt{3} [/tex]

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