JeremySmitherman34
JeremySmitherman34 JeremySmitherman34
  • 12-06-2017
  • Mathematics
contestada

Using the quadratic equation to solve 3x^2+11x-4=0, the value of b^2-4ac is
-26
73
169

Respuesta :

firestarangel26
firestarangel26 firestarangel26
  • 12-06-2017
Use standered form  to determine the values of a,b,and c. 
Standered form: 
[tex]ax^2+bx+c=0 [/tex]We are given: 
[tex]3x^2+11x-4[/tex]

a=3
b=11
c=-4

Plug the given values in the discriminant: 
[tex] b^2-4ac[/tex]
[tex] (11)^2-4(3)(-4) [/tex]
[tex]121-(4)(3)(-4)[/tex]
[tex]121-(12)(-4)[/tex]
[tex]121-(-48)[/tex]
[tex]121+48[/tex]

Final answer:169
Answer Link
robinvalenzuela333
robinvalenzuela333 robinvalenzuela333
  • 15-02-2019

Answer:

196

Step-by-step explanation:

Answer Link

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