mercedesrehs
mercedesrehs mercedesrehs
  • 03-03-2017
  • Mathematics
contestada

Log (C+3) base 3 - log (4C-1) base 3 = log 5 base 3

Respuesta :

jdoe0001 jdoe0001
  • 03-03-2017
[tex]\bf log_3(c+3)-log_3(4c-1)=log_3(5)\\\\ -----------------------------\\\\ log_{{ a}}\left( \frac{x}{y}\right)\implies log_{{ a}}(x)-log_{{ a}}(y)\qquad thus\\\\ -----------------------------\\\\ log_3\left( \frac{c+3}{4c-1} \right)=log_3(5)\implies \cfrac{c+3}{4c-1}=5[/tex]

solve for "c"
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