thandarw473 thandarw473

15-08-2022
Physics

contestada

A certain fan is capable of using 4800J of electrical energy each minute, converting 4000J of it into kinetic energy of the fan. What is the efficiency of this fan?

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15-08-2022

Answer:

Energy Ouput (Useful) / Total Energy Input = 4000 / 4800 = .833

E = 83% assuming 4800 is actually input to fan

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