ciuciu
ciuciu
02-02-2017
Mathematics
contestada
the limit of tan4x/6x as x approaches 0
Respuesta :
LammettHash
LammettHash
03-02-2017
[tex]\displaystyle\lim_{x\to0}\frac{\tan4x}{6x}=\lim_{x\to0}\frac{\sin4x}{4x}\times\frac{4x}{6x\cos4x}=\dfrac23\lim_{x\to0}\sec4x=\dfrac23[/tex]
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