Answer :
the probability of tossing three heads in a row
[tex]=\left( \frac{3}{8} \right)^{3} =\frac{27}{512} =0.052734375[/tex]
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the probability of tossing two heads followed by one tail
[tex]=\left( \frac{3}{8} \right)^{2} \times \left( \frac{5}{8} \right) =\frac{45}{512}[/tex]
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the probability of two heads and one tail in any order
[tex]=3\times \left( \frac{3}{8} \right)^{2} \times \left( \frac{5}{8} \right) =\frac{135}{512}[/tex]
