kayleigh2024 kayleigh2024

13-05-2022
Chemistry

contestada

Calculate the number of joules released when 75.0 grams of water are cooled from
100.0°C to 27.5°C

Respuesta :

okikiolu3 okikiolu3

13-05-2022

Answer:

-22750.5J or -2.28× 10⁴J

Explanation:

q=(75.0g)(4.184J)(27.5°C-100.0°C)

q= -22750.5J

q= -2.28× 10⁴J

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