Answer:
B
Step-by-step explanation:
using the rule of radicals
[tex]\sqrt{\frac{a}{b} }[/tex] × [tex]\sqrt{\frac{c}{d} }[/tex] = [tex]\sqrt{\frac{ab}{cd} }[/tex] , then
[tex]\sqrt{\frac{3x}{2} }[/tex] × [tex]\sqrt{\frac{x}{6} }[/tex]
= [tex]\sqrt{\frac{3x^2}{12} }[/tex]
= [tex]\sqrt{\frac{3x^2}{3(4)} }[/tex]
= [tex]\sqrt{\frac{x^2}{4} }[/tex]
= [tex]\frac{\sqrt{x^2} }{\sqrt{4} }[/tex]
= [tex]\frac{x}{2}[/tex]
