Answer:
The general term of the sequence is given by
T
n
=
a
n
2
+
b
n
+
c
The general term of the sequence is given by
T
n
=
a
n
2
+
b
n
+
c
Calculate a,b and c
Determine the 12th term of the sequence.
grade12 general-term sequence series
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T3 - 6=6
T3=12
then T2-T1=4
6-T1=4
T1=2
T4-T3=8
T4-12=8
T4=20
Therefore terms= 2,6,12,20
1st difference= 4,6,8
2nd difference= 2,2,....
2a=2
a=1
3a+b=4
3(1) + b=4
b= 1
a+b+c= 2
c= 2-1- 1= 0
giving Tn= n^2 + n
T12 = 12^2 + 12 = 156
