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Work Shown:
Sum the integers to get 222
(first)+(second)+(third)+(fourth) = 222
(x)+(x+1)+(x+2)+(x+3) = 222
4x+6 = 222
4x = 222-6
4x = 216
x = 216/4
x = 54 is the first integer
x+1 = 54+1 = 55 is the second integer
x+2 = 54+2 = 56 is the third integer
x+3 = 54+3 = 57 is the fourth integer
The sequence is 54, 55, 56, 57
Check:
54+55+56+57 = 222
