[tex]x+ y =15~~...(i)\\\\x-y = 5~~...(ii)\\\\\text{(i) +(ii):}\\\\x+y+x-y = 15+5\\\\\implies 2x = 20\\\\\implies x = \dfrac{20} 2 = 10\\\\\text{(i)-(ii):}\\\\x+y -x +y = 15 -5\\\\\implies 2y = 10\\\\\implies y=\dfrac{10}2 = 5\\\\\text{Hence the numbers are 10 and 5}[/tex]
