pikachu3089
pikachu3089 pikachu3089
  • 13-11-2021
  • Mathematics
contestada

Find the Solution in the Interval [0,2 pi]
tan(theta/7)+ square root3= 0

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sqdancefan
sqdancefan sqdancefan
  • 13-11-2021

9514 1404 393

Answer:

  no solution

Step-by-step explanation:

The solutions to the equation are ...

  tan(θ/7) +√3 = 0

  tan(θ/7) = -√3

  θ/7 = arctan(-√3) +nπ . . . . . . . for integer n

  θ = 7(-π/3 +nπ) = 7π(n -1/3)

For n=0, θ = -7π/3 -- not in the required interval.

For n=1, θ = 14π/3 -- not in the required interval.

There are no solutions in the required interval.

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