josie413
josie413
15-09-2021
Mathematics
contestada
Evaluate −2x^3+4y^2 when x=1 and y=5
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Аноним
Аноним
17-09-2021
Given, x = 1, y = 5
-2x^3+4y^2
= -2(1)^3+4(5)^2
= -2 + 4(25)
= -2 + 100
= 98
Answer is 98
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