Answer:
m‹EFG = m‹EFH + m‹HFG
• substitute:
[tex]130 \degree = 86 \degree + m \angle HFG \\ \\ m \angle HFG = 130 \degree - 86 \degree \\ \\ { \boxed{ \: \: m \angle HFG = 44 \degree}}[/tex]
