Answer:
Extracting out that inner right angle.
Hypotenuse = 8
Height = h
Adjacent :
[tex] = \frac{10}{5} = 2[/tex]
Height, h :
[tex]{ \tt{h = \sqrt{ {8}^{2} - {5}^{2} } }} \\ { \tt{h = \sqrt{64 - 25} }} \\ { \tt{h = \sqrt{39} }} \\ the \: height \: is \: { \boxed{6.2}} \: units[/tex]
