iamthebestxdepic iamthebestxdepic
  • 11-07-2021
  • Mathematics
contestada

if 2^x > 4^ 15 and x is a positive integer, what is the least possible value of x?

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 11-07-2021

Answer:

x = 31

Step-by-step explanation:

2^x > 4^ 15

Rewrite 4 as 2^2

2^x > 2^2^ 15

We know a^b^c = a^(b*c)

2^x > 2^ (2*15)

2^x > 2^30

Since the bases are the same, the exponents must follow the inequality

x> 30

Answer Link

Otras preguntas

I need some help please!!
what other events or things do you want to know more about from the Little Rock Nine? Have the answer as a question At least 3
Burning gasoline is an _____________ reaction.
team tool Bella canoed 15 3/4 miles in 5 1/4 hours
Should law enforcement agencies be allowed to use genetic information collected by private companies in criminal investigation
PLLLZZZZ!!! HELP!!! WILL GIVE BRAINLIEST!!!! Given a polynomial f(x), if (x − 6) is a factor, what else must be true? A. f(0) = −6 B. f(0) = 6 C. f(−6) = 0
Selecto two ratios that are equivalent to 3:12
A dilation has been performed on DEF. The length of segment EF is 10 cm and the length of segment E'F' is 5 cm. If segment DE has a length of 12 cm, what is the
3x-4y>12 which order pair (x,y) satisfies
would some one please solve part A for me I have been try to solve it for a while thank you very much .​