ac4atherybgekni0gh ac4atherybgekni0gh

12-12-2016
Mathematics

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Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution.

^ I really don't understand this topic, whatsoever. Could someone help?

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JcAlmighty JcAlmighty

13-12-2016

The answer is 4.

Square root of 2x plus 1 = 3:
[tex] \sqrt{2x+1} =3[/tex]

Square both sides:
[tex]( \sqrt{2x+1} )^{2} =3^{2} \\ \\ 2x+1=9 \\ 2x = 9 - 1 \\ 2x =8 \\ x = 8:2 \\ x =4 [/tex]

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