Answer:
[tex]\theta = 64.8^o[/tex]
Step-by-step explanation:
Given
[tex]h = 500m[/tex] --- altitude
[tex]x = 235m[/tex] --- horizontal distance
Required
The angle of elevation [tex]\theta[/tex]
The question is illustrated with the attached image.
From the attachment,
[tex]\tan(\theta) = \frac{h}{x}[/tex]
This gives:
[tex]\tan(\theta) = \frac{500m}{235m}[/tex]
[tex]\tan(\theta) = 2.128[/tex]
Take arctan of both sides
[tex]\theta = \tan^{-1}(2.128)[/tex]
[tex]\theta = 64.8^o[/tex]
