Answer:
[tex](f-g)(x)=x^2-4x-21[/tex]
Step-by-step explanation:
We are given the two functions:
[tex]f(x)=x^2-3x-28\text{ and } g(x)=x-7[/tex]
And we want to find:
[tex](f-g)(x)[/tex]
This is equivalent to:
[tex]=f(x)-g(x)[/tex]
Substitute:
[tex]=(x^2-3x-28)-(x-7)[/tex]
Distribute:
[tex]=x^2-3x-28-x+7[/tex]
Rearrange:
[tex]=(x^2)+(-3x-x)+(-28+7)[/tex]
Hence:
[tex](f-g)(x)=x^2-4x-21[/tex]
