Respuesta :

tonb

Answer:

#include <iostream>

using namespace std;

int main() {  

 int n = 1000;

 int sum = 0;

 while(n <= 2000) {

   sum += n;

   n += 2;

 }

 cout << "sum of even numbers in [1000..2000] = " << sum << endl;

}

Explanation:

This will output:

sum of even numbers in [1000..2000] = 751500