solianatesfaye59
solianatesfaye59 solianatesfaye59
  • 03-05-2021
  • Mathematics
contestada

Twice a number x exceed 5 at least by 4. find the possible value of x.

Respuesta :

BoxBoyo
BoxBoyo BoxBoyo
  • 03-05-2021

Answer:

5?

Step-by-step explanation:

2x › 5 (buy at least 4)

so you can just start plugging numbers in.

I used 5, 5 times 2 is 10 which is 5 more that 5, which does met the quota.

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ivycoveredwalls
ivycoveredwalls ivycoveredwalls
  • 03-05-2021

Answer:

[tex]x \ge 4.5[/tex]

Step-by-step explanation:

The number 2x is larger than 5, so  2x - 5  is the difference between 2x and 5.  This difference is at least (greater than or equal to) 4.

[tex]2x-5 \ge 4\\\\2x \ge 9\\\\x \ge 4.5[/tex]

Answer Link

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