Respuesta :

devishri1977

Answer:

Step-by-step explanation:

In ΔBCA and ΔDCA,

BC ≅ CD                 Given

∠BCA ≅∠DCA        Given

AC ≅ AC                    Reflexive property

ΔBCA ≅ ΔDCA          S A S congruent

∵ BA ≅ AD                CPCT {Corresponding part of congruent triangle}