Answer:
[H⁺] = 5.754 x 10^-13 M
Explanation:
Since pH is the negative log of the hydronium concentration, we can solve for hydronium concentration and then plug in our given pH:
pH = -log[H⁺]
-pH = log[H⁺]
10^-pH = [H⁺]
Let's plug in our pH:
[H⁺] = 10^-pH = 10^-12.24 = 5.754 x 10^-13 M
