Respuesta :

mathstudent55

Answer:

[tex] x = \dfrac{5}{2} \pm {\dfrac{\sqrt{57}}{2} [/tex]

Step-by-step explanation:

[tex] x^2 - 5x = 8 [/tex]

[tex] x^2 - 5x + \dfrac{25}{4} = 8 + \dfrac{25}{4} [/tex]

[tex] (x - \dfrac{5}{2})^2 = \dfrac{57}{4} [/tex]

[tex] x - \dfrac{5}{2} = \pm \sqrt{\frac{57}{4}} [/tex]

[tex] x = \dfrac{5}{2} \pm {\dfrac{\sqrt{57}}{2} [/tex]

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