Answer:
[tex]\frac{3}{x}+\frac{x}{x+2}= \frac{x^2+3x+6 }{x^2+2x}[/tex]
Step-by-step explanation:
Given
[tex]\frac{3}{x}+\frac{x}{x+2}[/tex]
Required
Solve
[tex]\frac{3}{x}+\frac{x}{x+2}[/tex]
Take LCM
[tex]\frac{3(x+2) + x * x}{x(x+2)}[/tex]
[tex]\frac{3(x+2) + x^2}{x(x+2)}[/tex]
Open brackets
[tex]\frac{3x+6 + x^2}{x^2+2x}[/tex]
Rewrite as:
[tex]\frac{x^2+3x+6 }{x^2+2x}[/tex]
Hence:
[tex]\frac{3}{x}+\frac{x}{x+2}= \frac{x^2+3x+6 }{x^2+2x}[/tex]
