Answer:
0.00032 M
Explanation:
From the question,
Applying the for pH
pH = -log[H⁺]............... Equation 1
Where H⁺ = Hydrogen ion concentration of Hydrochloric acid
Given: pH = 3.50
Substitute into equation 1 and solve for H⁺
3.50 = -log[H⁺]
Taking the log inverse of both side,
H⁺ = 10⁻⁽³⁵/¹⁰⁾
H⁺ = 0.00032 M
Hence the H⁺ of Hydrochloric acid is 0.00032 M
