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01-03-2021
Chemistry

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A 1.00 L of a solution is prepared by dissolving 125.6 g of NaF in it. What would be the molarity of this solution?

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maacastrobr maacastrobr

03-03-2021

Answer:

2.99 M

Explanation:

In order to solve this problem we need to keep in mind the definition of molarity:

Molarity = moles of solute / liters of solution

In order to calculate the moles of solute, we convert 125.6 g of NaF into moles using its molar mass:

125.6 g NaF ÷ 42 g/mol = 2.99 mol NaF

As the volume is already given, we can proceed to calculate the molarity:

Molarity = 2.99 mol / 1.00 L = 2.99 M

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