kaitlynworley0103
kaitlynworley0103 kaitlynworley0103
  • 15-02-2021
  • Mathematics
contestada

Solve for n.
19n+20≥1

Respuesta :

10n31y
10n31y 10n31y
  • 15-02-2021

[tex]19n + 20 \geqslant 1[/tex]

[tex]19n + 20 - 20 \geqslant 1 - 20[/tex]

[tex]19n \geqslant - 19[/tex]

[tex] \frac{19n}{19} \geqslant \frac{ - 19}{19} [/tex]

[tex]n = - 1[/tex]

Answer Link
marierodriguez1008
marierodriguez1008 marierodriguez1008
  • 15-02-2021

Answer:

[tex]n\geq -1[/tex]

Step-by-step explanation:

[tex]19n+20\geq 1[/tex]

[tex](19n+20)+(-20)\geq 1+(-20)[/tex]

[tex]19n\geq -19[/tex]

[tex]\frac{19n}{19} \geq \frac{-19}{19}[/tex]

[tex]n\geq -1[/tex]

Answer Link

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