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  • 11-02-2021
  • Mathematics
contestada

Solve (Y+5)^3/2=4 where y is a real number

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betir373
betir373 betir373
  • 11-02-2021

Answer:

[tex]y {}^{2} + 10y = - 33.5[/tex]

Step-by-step explanation:

(y+5)(y+5)x3/2=4

Y(y+5)+5(y+5) x 3/2=4

[tex]y {}^{2} + 5y + 5y + 25 \times 3 \2 = 4[/tex]

[tex]y ^{2} + 10y + 75 \2 = 4[/tex]

[tex]y {}^{2} + 10y + 37.5 = 4[/tex]

[tex]y {}^{2} + 10y = 4 - 37.5[/tex]

[tex]y {}^{2} + 10y = - 33.5[/tex]

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