abigailbarnes8242 abigailbarnes8242
  • 04-02-2021
  • Mathematics
contestada

Solve the equation for x:
sin^2 x – 2 cos x - 2 = 0
for the restriction 0 < x < 2pi

Solve the equation for x sin2 x 2 cos x 2 0 for the restriction 0 lt x lt 2pi class=

Respuesta :

Аноним Аноним
  • 04-02-2021

Answer: x = pi

sin²x - 2cos x - 2 = 0

⇔ 1 - cos²x - 2cos x - 2 = 0

⇔ cos²x + 2cos x + 1 = 0

⇔ (cos x + 1)² = 0

⇒ cos x + 1 = 0

⇔ cos x = -1

⇒ x = pi + k2pi

because 0 ≤ x < 2pi

=> x = pi

Step-by-step explanation:

Answer Link

Otras preguntas

what is national library week?
Plz help... 6b - 49 =2(b - 3)
how do I expand r(r-r2) the 2 is meant to be r squared
1 . A farmer moves along the boundary of his rectangular field of side 10m x 20m . farmer covers 1m in 1sec . what will be the magnitude of displacement at the
what does 'chop and change' mean?
A body of mass 2 kg is moving in the positive X-Direction with a speed of 4 m/s collides head on with an another body of mass 3 kg moving in the negative X-Dire
The smallest and the largest whole numbers that round to 70 when rounded to the nearest ten. What are the numbers....
What Is a Cause-Effect Essay?
what do you set the oven to when baking palmiers
Calculate the de Broglie wavelength of an electron traveling at 3.0 × 107 m/s (me = 9.1 × 10-31 kg).