hawrapotato16
hawrapotato16 hawrapotato16
  • 15-01-2021
  • Physics
contestada

Calculate the extension of a 20cm spring that has a spring contrast of 45000N/m and 1500N of elastic potential energy.

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rafaleo84
rafaleo84 rafaleo84
  • 15-01-2021

Answer:

See the answer below

Explanation:

The elastic potential energy can be calculated by means of the following equation:

[tex]E_{el}=\frac{1}{2} *k*x^{2}[/tex]

where:

Eel = elastic energy = 1500 [J]

k = spring constant = 45000 [N/m]

x = extension [m]

[tex]1500=\frac{1}{2} *45000*x^{2} \\3000=45000*x^{2} \\x=\sqrt{0.06666}\\x=0.258[m] = 25.8 [cm][/tex]

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