Answer:
0.5195 liters of water
Explanation:
First we convert 15.4 grams of barium sulfide (BaS) into moles, using its molar mass:
- 15.4 g ÷ 169.39 g/mol = 0.0909 mol
Then we calculate the required volume of water, using the definition of molarity:
- molarity = moles / volume
- 0.175 M = 0.0909 mol / Volume
