Answer:
[tex]g(f(2)+3)=30[/tex]
Step-by-step explanation:
We have the two functions:
[tex]g(t)=t^2-t\text{ and } f(x)=1+x[/tex]
And we wish to find:
[tex]g(f(2)+3)[/tex]
First, let’s find f(2) first. So, we will substitute 2 for x for f(x):
[tex]f(2)=1+(2)=3[/tex]
Hence, we can now substitute 3 for f(2):
[tex]g(f(2)+3)=g(3+3)=g(6)[/tex]
Now, we can find g(6). Substitute 6 for t for g(t):
[tex]g(6)=(6)^2-(6)=36-6=30[/tex]
Therefore:
[tex]g(f(2)+3)=30[/tex]
