Answer:
(a) >, decreasing
(b) 0, horizontal
Step-by-step explanation:
(a) dy/dt = eᵗ (y − 1)²
eᵗ is always positive, and (y − 1)² is always positive. So dy/dt is always positive. Meaning the graph of the solution can never be decreasing.
(b) When y = 1, dy/dt = e¹ (1 − 1)² = 0. However, this graph does not have a horizontal tangent line at y=1, so this is not the solution of the differential equation.
