20064871
20064871 20064871
  • 13-11-2020
  • Mathematics
contestada

Write the equation of the line y=(5)/(6)x+(7)/(6) perpendicular to
that passes through the point (-8,7)

Respuesta :

ackahedem582
ackahedem582 ackahedem582
  • 13-11-2020

Answer:

6x + 5y + 13 = 0.

Step-by-step explanation:

y = 5/6x + 7/6

Gradient = 5/6

Since the line is perpendicular to y = 5/6x + 7/6

then its gradient is -6/5.

Hence its equation is: point (-8,7).

y - 7 = -6/5(x -(-8))

multiplying through by 5 we get;

5y - 35 = -6(x + 8)

5y - 35 = -6x - 48

6x + 5y + 13 = 0

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