[tex] \frac{1}{2} [/tex]a - 7 < [tex] \frac{2}{3} [/tex]a - 9 Give the fractions a common denominator. (2 and 3 both go into 6)
[tex] \frac{3}{6} [/tex]a - 7 < [tex] \frac{4}{6} [/tex]a - 9 Subtract [tex] \frac{3}{6} [/tex]a from both sides
-7 < [tex] \frac{1}{6} [/tex]a - 9 Add 9 to both sides
2 < [tex] \frac{1}{6} [/tex]a Multiply both sides by 6 to cancel out the fraction
12 < a Flip the inequality to make it easier to read
a > 12
