Search ResultsLet L denote the line of intersection. Then v = a × b = (1 − 1,−(−2 − 1),2 − (−1)) = (0,3,3) is parallel to L. We only need to find a point P on L. To find P, solved the system of equations of the planes: 2x − y + z = 5 and x + y − z = 1. We consider P to be the point of L on the plane z = 0.
