ijustwannaknow11 ijustwannaknow11
  • 13-06-2020
  • Mathematics
contestada

A woman is now 30 years older than her son. 15 years ago, she was twice as old. What are the present ages of the woman and her son?

Respuesta :

mhanifa
mhanifa mhanifa
  • 13-06-2020

Answer:

75 and 45

Step-by-step explanation:

woman's age= w

son's age= s

--------------

  • w=s+30
  • w-15=(s-15)*2 ⇒ w-15=2s-30 ⇒ w=2s- 15

comparing the two above:

  • s+30=2s-15  ⇒ s= 45 ⇒ w= 75

Answer Link

Otras preguntas

Help me on this plz...
What is the recursive rule for the sequence? 3, −1, 1/3, −1/9, ...
how many stars our thier in the universe​
what is anne franks charater traits
What type of link is used to call this file?
Can anyone help me do this please ?
why nitro group is called an ambident group?​
I have 300 beads. My sister has 60 more beads than I did. How many beads do my sister and I have altogether?​
Use the quadratic formula to find the solutions to the equation. X^2-3x+1=0
What is journalism based on todays world?